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12x^2-74x+112=0
a = 12; b = -74; c = +112;
Δ = b2-4ac
Δ = -742-4·12·112
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-10}{2*12}=\frac{64}{24} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+10}{2*12}=\frac{84}{24} =3+1/2 $
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